What is the equivalent power of a combination of a +16D stand magnifier with a +2.00 add, separated by 25 cm?

Study for the OptoPrep National Board of Examiners in Optometry (NBEO) Test. Prepare with flashcards and multiple choice questions, each with hints and explanations. Get ready for your exam success!

To determine the equivalent power of a combination of a +16D stand magnifier and a +2.00 add, with the two elements separated by a distance of 25 cm, we need to consider how magnifying systems work.

First, the +16D stand magnifier has a focal length of 1/16 meters, which is about 6.25 cm. Because the magnifier is designed to be used at a comfortable distance, it provides magnification for objects placed within its focal length.

The +2.00 add also implies that there will be an additional power provided for near vision correction, particularly useful for individuals who require additional convergence for viewing near objects.

To find the equivalent power of these two optical devices separated by a distance, we can use the formula for equivalent power (P_eq), which incorporates the distance (d) between them:

[ P_{eq} = P_1 + P_2 - \frac{P_1 \cdot P_2}{d} ]

Where:

  • ( P_1 ) is the power of the first optical element (+16D),

  • ( P_2 ) is the power of the second optical element (+2D),

  • ( d ) is

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